EXAMPLE: CALCULATING GENE AND GENOTYPE FREQUENCIES
In the Durham area, the morning glory Ipomoea purpurea exhibits variation for flower color. Genotype at the W locus determines flower color. In natural populations there are two alleles W and w. The phenotype associated with each genotype is as follows:
WW--darkly pigmented
Ww--lightly pigmented
ww--unpigmented (except for rays, or nectar guides)
Suppose that in a population we go out and count the number of individuals of each phenotype. Then, the numbers of individuals for each genotype can be designated as follows:
Number Genotype
25
WW
25
Ww
50
ww
Then the genotype frequencies are
pAA = 25/(25+25+50) = 0.25
pAa = 25/(25+25+50)
= 0.25
paa =
50/(25+25+50) = 0.50
and the gene frequencies are
pA = (2x25 + 25)/(2x100) = 0.25 + (1/2) 0.25 = 0.375
pa = 1 - pA
= (2x50 + 25)/(2x100) = 0.5 + (1/2) 0.25 = 0.625
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